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OpenStudy (shamim):
nPr=n!/(n-r)!
OpenStudy (shamim):
8P3=8!/(8-3)!
OpenStudy (yanasidlinskiy):
Do you understand how to do it? @KendrickLamar2014
OpenStudy (shamim):
5!=?
OpenStudy (yanasidlinskiy):
The formula you would use is \[nPr=\frac{ n! }{ (n-r)! }\]
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OpenStudy (kendricklamar2014):
yes
OpenStudy (yanasidlinskiy):
Next you would \[\frac{ 8! }{ (8-3)! } = \frac{ 8! }{ 5! } = \frac{ 8*7*6*5*4*3*2*1 }{ 5*4*3*2*1 }\]
OpenStudy (anonymous):
That is a partial permutation, \[nPk=\frac{ n! }{ (n-k)! } \rightarrow 8P3 =\frac{ 8! }{ (8-3)! }=\frac{ 8! }{ 5! }= 6\times7\times8= 336\]
OpenStudy (kendricklamar2014):
So the answer is B
OpenStudy (anonymous):
Yes
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OpenStudy (yanasidlinskiy):
DO you have a calculator handy? If so, Use of what I did. Multiply the top and multiply the bottom. Then divide it and that would be your final answer!:) Good Luck!
OpenStudy (kendricklamar2014):
40320/120= 336
OpenStudy (anonymous):
It's easier if you cancel them out
OpenStudy (anonymous):
5! = 5*4*3*2*1
OpenStudy (anonymous):
and 8! = 8*7*6*5*4*3*2*1
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OpenStudy (anonymous):
Just cancel the 5*4*3*2*1 Because they`re dividing and it is multiplying both