Limit-Can limit be squared on both sides?
hell yes ... but you can't take back square root
@experimentX for example, if lim(x-->0)sqrt(ax+b)=x+2 Can it be written as lim(x-->0)(ax+b)=(x+2)^2
hmm ... no!! you never get this type of limit. lim(x-->0)sqrt(ax+b)=x+2 ^^ there cannot be variable 'x' on this side.
\[\lim \limits_{x\to 0} (1+x)^ {\frac{1}{x}} = k\]
if u try to take x power both sides... im not sure.. it just doesnt look right
lol ... you can't take variable as ^ on both sides.
hahah yes :) \[\large \lim \limits_{x\to 0} (1+x)^ {\frac{1}{n}} = k\]
taking nth power both sides is legal ?
this like proving 1=2 via derivative x^2
but not sure about 1/n th
Perhaps you can try for something more general. Suppose \(g\) is continuous and we have \(\lim_{x \to n} f(x) = L\) Does it hold that \(\lim_{x \to n} g(f(x)) = g(L)\)
taking n-th power you get, yes yes of course you can do it ... \[ \lim_{x \to n} g(f(x)) = g \left( \lim_{x\to 0 }f(x) \right) = f(L)\]
sorry ... g(L) but not sure about taking power 1/n th
@Alchemista yes it holds,we can multiply the same value on both sides. But,it is confusing about the square?
Why? Let g(x) = x^2
define g(x) = x^2 in above, you get the result immediately.
You still need to prove the so called "composition law" of limits via first principles if you want a rigorous proof. You will need to appeal to definition of limit, the epsilon-delta definition.
that limit works like a chain rule ... chain rule of logic.
It is indeed similar logic.
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