Question

Reduce the following rational expression to lowest terms, if possible.
(Problem in comments)

Answer 1

\[\frac{ 7x+21 }{ 7x^2+42x+63 }\]

Answer 2

first factor 7 from the denominator and numerator
then, it will be easier to factor the quadratic in denominator :)

Answer 3

\[\frac{ 7(x+3) }{ 7(x+3)^2 }\]
two of the 7(x+3)s cancel out & im left with one on the bottom sooooo...
\[\frac{ 1 }{ 7(x+3) }\]

Answer 4

Internet went out...

Answer 5

the 7 also cancels out from numerator and denominator!

Answer 6

So only the x+3 is a square? not the 7? oh ok

Answer 7

\(\huge \dfrac{ \cancel 7\cancel {(x+3)} }{\cancel 7(x+3)^\cancel 2 }\)

Answer 8

Wait, duh...what am i saying lol i got it now