Question

If a^2 = by + cz, b^2 = cz +ax, c^2 = ax +by then the value of x/(a+x) + y/(b+y) + z/(c+z) = a.) a+b+c, b.) (1/a) + (1/b) + (1/c) c.) 1 d.) 0

Answer 1

now multiply both num and denom of x/(a+x) by a we then have
ax/(a^2 +ax)
we know a^2 = by + cz
hence
ax/(a^2 +ax) becomes ax/( by + cz +ax)

Answer 2

cna you do it further

Answer 3

now multiply both num and denom of y/(b+y) by b and that of
z/(c+c) by c ..

Answer 4

x/(a+x) + y/(b+y) + z/(c+z)
=ax/(a^2 +ax) + by/(b^2+by) + cz/(c^2+cz)

Answer 5

use
a^2 = by + cz,
b^2 = cz +ax,
c^2 = ax +by

then we have
ax/(ax+by+cz) + by/(ax+by+cz) +cz/(ax+by+cz)
=(ax+by+cz)/(ax+by+cz)
=1

Answer 6

Thank you! Really appreciated...