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OpenStudy (acxbox22):
of??
OpenStudy (anonymous):
\[\frac{ x^{2} + x -2 }{ x^{2} -3x -4 }\]
OpenStudy (yanasidlinskiy):
Do you know what domains and ranges are??
OpenStudy (anonymous):
No I don't know
OpenStudy (anonymous):
the domain is the x value and the range is the y value
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OpenStudy (anonymous):
What exactly do you mean by the value
OpenStudy (anonymous):
so in the coordinate pair (2,3) the domain in 2 and the range is 3
OpenStudy (anonymous):
Oh okay, how do i find it?
OpenStudy (anonymous):
do you have a problem/question you need to solve?
OpenStudy (anonymous):
Yes, the one I gave above
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OpenStudy (anonymous):
ok the one that you are dividing the polynomials
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
ok what is \[x^2/x^2\]
OpenStudy (anonymous):
1
OpenStudy (anonymous):
yes now what is x/-3x
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OpenStudy (anonymous):
do you know
OpenStudy (anonymous):
not exactly, i don't remember how i would even solve that
OpenStudy (anonymous):
ok what you have to do is divide \[x/-3x\] and you will have to cancel out the x's to get 1/3 for that part
OpenStudy (anonymous):
so that will be \[\frac{ 1 }{ 3 }\] and will i do the same for\[\frac{ -2 }{ 4}\]
OpenStudy (anonymous):
yes exactly
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OpenStudy (anonymous):
So i would end up with this \[1 +\frac{ 1 }{ 3 } -\frac{ 1 }{ 2 }\] correct?
OpenStudy (anonymous):
yes thats correct
OpenStudy (anonymous):
What would I do after this?
OpenStudy (anonymous):
simplify and answer
OpenStudy (anonymous):
Okay I know this is way back but how would I simplify fractions
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OpenStudy (anonymous):
if u dont mind what grade r u in
OpenStudy (anonymous):
11
OpenStudy (anonymous):
ok how you simplify fractions is you have to find the GCFf of the denominator
OpenStudy (anonymous):
i mean LCM AND THEN MAKE A PROPORTION
OpenStudy (anonymous):
Im sorry for going back to simplifying fractions. The LCM is 6 and if i remember it right don't I multiple the numerator and then add the two equations?
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