Question

factoring:

Answer 1

describe and correct the error made in factoring completely.
4x^4+12x^3+8x^2+24x=4(x^4+3x^3+2x^2+6x)
=4[x^3(x+3)+2x(x+3)]
=4(x^3+2x)(x+3)

Answer 2

the only thing I can see is the omission of the square brackets in the last step

Answer 3

its number 35

Answer 4

i can see that document i'm sfraid

Answer 5

cant see it?

Answer 6

well how am i supposed to show it to you then?

Answer 7

ok i've managed to expand it
i cant see anything else wrong
- but thats not really an error
its the same without square brackets

Answer 8

are you sure?

Answer 9

yes - perhaps its a catch question

Answer 10

oh okay well can i ask you other questions about factoring?

Answer 11

ok

Answer 12

why can you factor the same polynomial using different pairs of terms?

Answer 13

describe how to factor the expression 6x^5+4x^4+12x^3+8x^2+9x+6.

Answer 14

try to do this by grouping
9x + 6 = 3 (3x + 2)
6x^5 + 4x^4 = 2x^4(3x + 2)
and
12x^3 + 8x^2 = 4x^2 (3x + 2)

so we have 3x + 2 common to all 3
so we can write

(3x + 2)( 2x^4 + 4x^2 + 3)

Answer 15

now we have a trinomial in the second bracket which might be factorable..

Answer 16

no its not so thats the final answer

Answer 17

ok?

Answer 18

yes I was looking at a binomial of the form

(2x^2 + a)(x^2 + b) for the second bracket but the numbers will not fit

Answer 19

your confusing me?

Answer 20

compare it with a trinomial which factorises
2x^2 +5x + 3)
= 2x^2 + 2x + 3x + 3
= 2x(x + 1) + 3(x + 1)
= (2x + 3)((x + 1)

Answer 21

theers no way can you get whole numbers to get 4x as the middle term