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Mathematics 11 Online
OpenStudy (anonymous):

Succession 1. A=(0,1,5,23,...) 2. C=(1,4,27,64,...)

OpenStudy (anonymous):

I think C=n^n but it doesnt match for 64

OpenStudy (amistre64):

trying to find a pattern?

OpenStudy (anonymous):

sure it does!

OpenStudy (amistre64):

1 4 27 64 3 23 37 20 14 -6 hmm, a difference tier is not getting something thats for sure, but it can produce a sequence that matches the first 4 terms regardless 1 + 3n + 20n(n-1)/2 - 6n(n-1)(n-2)/6 1 + 3n + 10n(n-1) - n(n-1)(n-2) http://www.wolframalpha.com/input/?i=table+%5B1+%2B+3n+%2B+10n%28n-1%29+-+n%28n-1%29%28n-2%29%5D%2C+n%3D0..5

OpenStudy (anonymous):

what is wrong with \(n^n\)?

OpenStudy (anonymous):

ooh i see doh, i thought \(4^4=64\) but in fact my arithmetic is not what it ought to be ...

OpenStudy (amistre64):

it should be noted that since the difference tiers do not reach a conclusive constant ... that this may not be the 'correct' rule for the given sequence, all we can say for sure is that it produces the first set of terms that are given.

OpenStudy (anonymous):

\[0,1,5,23,\] \[1^2-1,2^2-3,3^2-4,4^2-5\] nope i must be missing something

OpenStudy (amistre64):

i came up with an integration from 0 to n, for one of my sequence generators ... i finally had to show my teacher that the wolf agreed with me before she accepted it as valid :)

OpenStudy (anonymous):

wonder what the gimmick is here it is not a very nice polynomial probably something else going on that i don't see

OpenStudy (anonymous):

Neither do I, something is wrong on it

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