Hey guy's I need help ASAP. Thx's!! : )

Question

Hey guy's I need help ASAP. Thx's!! :  )

i_love_my_nieces · Answer

Which is  = 300 J over P solved for J?

i_love_my_nieces · Answer

J=300PM

 J= 300M
     ----
        P

J= 300
    ----
     PM

J= PM
    ----
     300

i_love_my_nieces · Answer

@bibby can you help me pretty please?

i_love_my_nieces · Answer

@AccessDenied can you please help me?

accessdenied · Answer

? = 300 J over P
What is the left side?  M?

i_love_my_nieces · Answer

$$M=\frac{ 300 J }{ P }$$

accessdenied · Answer

Ah, alright.

Well our interest is solving for J.  So we should perform operations on both sides of the equation that cancel with what is attached to J.
$ M = \dfrac{300 J}{P}  $    Here, P is being divided off, so we could multiply both sides by P to cancel the P on the right.
$ M \times P = \dfrac{300 J}{P} \times P $
$ PM = 300 J $
And then 300 is multiplied onto it, so can you see the next step is to divide both sides by 300 to get our answer?

i_love_my_nieces · Answer

Do you mean @AccessDenied $$J=300PM$$

i_love_my_nieces · Answer

I think it's B?

accessdenied · Answer

No, carefully see what has been done here.  We want to move everything onto the other side and get J alone on the right.  So we can start with multiplication of P to both sides...
  $ M = \dfrac{300 \color{red}J}{P} $
Multiply both sides by P, cancels with division by P
  $ M \times P = \dfrac{300 \color{red}J}{P} \times P $
  $ PM = 300 \color{red} J $
But at this point, we have not solved for J yet.  We need everything else on the other side, so the 300 multiplied onto J has to go as well.  To cancel multiplication, we divide both sides by 300:
  $ \dfrac{PM}{300} =\dfrac{300 \color{red}J}{300} $

i_love_my_nieces · Answer

So...

i_love_my_nieces · Answer

If it's not B, then could it be C?

accessdenied · Answer

Maybe I should go back a bit.  You understand our goal is to get J alone, yea? 
From $ M = \dfrac{300\color{red}J}{P} $  to  $ something = \color{red} J $  <-- J is alone.

And that we can do any operation onto both sides of an equation so that it remains equal.
  $a = b$   implies  $a + c = b + c$,  $ac = bc$,  $\dfrac{a}{c} = \dfrac{b}{c} $, and $a - c = b - c$

These details are familiar?

anonymous · Answer

you are over complicating this simple algebraic equation. if you are solving for j, first get rid of p by multiplying it on both sides to cancel it out on one side. so you will have pm=300j, then divide the 300 by both sides to leave j by itself and you will get 300/pm=j

anonymous · Answer

so for you its D

i_love_my_nieces · Answer

OK, thank you

anonymous · Answer

np