Question

The answer is approximately 22, but I can't figure out how to get there.

33=31.5+1.1log(x+1)

Answer 1

\[33=31.5+1.1\log(x+1)\]subtract 31.5 from both sides,

\[1.5=1.1~\log(x+1)\]divide both sides by 1.1\[1.36=\log(x+1)\]

can you take it from here ?

Answer 2

That's actually the part I'm stuck on. Am I just suppose to take the log of both sides?

Answer 3

\[1.36=\log(x+1)\]unspecified base,\[1.36=\log_{10}(x+1)\]
Now, focus and follow....
\[1.36=\log_{10}(x+1)\]\[1.36 \times \log_{10}10=\log_{10}(x+1)\]\[ \log_{10}10^{1.36}=\log_{10}(x+1)\]\[10^{1.36}=(x+1)\]

can you do it from here ?

Answer 4

Ah, I see now. I can take it from there. Thank you so much!

Answer 5

You are welcome, always remember this tip, of using
\[\log_xx~~(The~~magic~~1)\]