Question

I need help finding the equivalent expression to this integral: The integral from 0 to 1 of 3x(x^2-5)^8 dx?
I know that it has to be 1/6 integral from 0 to 1 of u^8 du or 1/6 integral from -5 to -4 u^8 du

Answer 1

i think the one sixth is wrong out front

Answer 2

\[u=x^2-5, du=2xdx\]
\[\frac{3}{2}\int u^8du\]

Answer 3

oh how did you get the 3/2?

Answer 4

I took the integral but I really am not sure how I am supposed to get the average.

Answer 5

you got \(3xdx\) already