Question

So confused...
If the rotating mass m is doubled and everything else remains unchanged, the speed of the new mass would be...?

Answer 1

@Nali <3

Answer 2

ok use ma= v^2/r

so if 2m means 2a and 4v(elocity) because (2v)^2= 4v

Answer 3

The answer says that it's v / (square root of 2) ?

Answer 4

ok so you r looking for velocity then

Answer 5

yep!

Answer 6

..still confused..

Answer 7

If the force and radius remains constant:
v1 = velocity before mass doubles
v2 = velocity after mass doubles

Eq. #1 F = m * v1^2 ÷ r
Eq. #2 F = (2 * m) * v2^2 ÷ r

We have 2 equations for F, so set then equal to each other!!
(2 * m) * v2^2 ÷ r = m * v1^2 ÷ r
divide both sides by m

2 * v2^2 ÷ r = v1^2 ÷ r
multiply both sides by r

2 * v2^2 = v1^2
Square root both sides
√2 * v2 = v1
Divide both sides by √2
v2 = v1 ÷ √2


from yahoo https://answers.yahoo.com/question/index?qid=20101207213127AAQnFvU