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Mathematics 10 Online
OpenStudy (anonymous):

162x^5y^2-32xy^2

OpenStudy (anonymous):

What are you trying to do?

OpenStudy (anonymous):

Factor completely. I'm not sure how to do these types of problems and my HW is due in 2 hours. :/

OpenStudy (anonymous):

Tell me the coefficients you see in your question

OpenStudy (anonymous):

162, -32

OpenStudy (anonymous):

okay so what is the greatest common denominator of both coefficients?

OpenStudy (anonymous):

Sorry for the slow reply there... Well we see that they are factorable by 2 and they can also be factorable by one x and y^2... Thus 2xy^2(81x^4-16) is the answer

OpenStudy (anonymous):

that is the answer^

OpenStudy (anonymous):

So 2 is the GCD?

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

Thank you both so much! :)

OpenStudy (anonymous):

No problem at all ^_^

OpenStudy (anonymous):

I typed that answer in and it's saying it's wrong...

OpenStudy (anonymous):

hmm something else should be factored then

OpenStudy (anonymous):

There is nothing that can be factored left...

OpenStudy (anonymous):

81 is uneven... 16 is even... they share no common factor

OpenStudy (anonymous):

OrthodoxMan, did you get a different answer?

OpenStudy (anonymous):

well that i know but there has to be something wrong with the answer and no i got the same as him

OpenStudy (anonymous):

Super weird... Guess I'll leave it blank and ask my professor tomorrow. Thank you! :)

OpenStudy (anonymous):

are you sure? im known to not give up

OpenStudy (anonymous):

haha if you want to try and figure it out you are welcome and I'll keep putting whatever answers you get.

OpenStudy (anonymous):

I copied and pasted exactly as it is on my HW: 162x^{5}y^{2}-32xy^{2}

OpenStudy (anonymous):

alright show me the screenshot saying it's wrong with the answer

OpenStudy (anonymous):

K. hang on... Gotta get my phone.

OpenStudy (anonymous):

The answer is wrong, it could be reduced further

OpenStudy (anonymous):

It can? Are you going to make me figure it out?

OpenStudy (anonymous):

well what do you want me to do? Tell you the answer and then explain after?

OpenStudy (anonymous):

sure... lol

OpenStudy (anonymous):

lol alright you better not run away after i tell you :P

OpenStudy (anonymous):

I definitely won't.

OpenStudy (anonymous):

the answer is 2xy^2(9x^2 +4)(3x-2)(3x + 2)

OpenStudy (anonymous):

:) you're awesome! Now tell me how you did that.

OpenStudy (anonymous):

awesomee alright so you already have your greatest common denominator factored out along with the highest powers right?

OpenStudy (anonymous):

Right...

OpenStudy (anonymous):

Do you get what i mean by highest powers?

OpenStudy (anonymous):

5?

OpenStudy (anonymous):

nope If i say the highest power that can be factored out I mean like the lowest exponent that exists in the equation So what we had was: 162x^5y^2-32xy^2 The lowest exponent for x is 1 and that can be seen in 32x^1y^2 Notice we dont show x^1 but we write it as x What is the lowest exponent for y?

OpenStudy (anonymous):

:/ this gives me a headache. Lowest exponent for y, 1?

OpenStudy (anonymous):

2?

OpenStudy (anonymous):

there you go :)

OpenStudy (anonymous):

:) lol thank you! Can you come do my final on Wednesday for me?

OpenStudy (anonymous):

i hope that headache has disappeared for now We're not done yet

OpenStudy (anonymous):

Oh man! OK..

OpenStudy (anonymous):

what we have after factoring the highest power and the greatest common denominator is 2xy^2(81x^4 - 16)

OpenStudy (anonymous):

what do you notice about the two coefficients in the bracket?

OpenStudy (anonymous):

I do not know. I'm telling you I'm horrible at math.

OpenStudy (anonymous):

Haha dont worry, we'll work on that together Do you know what perfect squares are?

OpenStudy (anonymous):

No. haha

OpenStudy (anonymous):

lol well that is what we're going to do next I'll make this real short What is the answer to 3^2?

OpenStudy (anonymous):

9

OpenStudy (anonymous):

that my friend is a perfect square What about 4^2?

OpenStudy (anonymous):

16

OpenStudy (anonymous):

;)

OpenStudy (anonymous):

and 9^2?

OpenStudy (anonymous):

81

OpenStudy (anonymous):

ah I got it!

OpenStudy (anonymous):

yeahh now what do you think happens to this: 2xy^2(81x^4-16)

OpenStudy (anonymous):

I think... So we just had to figure out what goes into 81 and 16?

OpenStudy (anonymous):

which was 9 for 81 and... now I'm lost again...

OpenStudy (anonymous):

dont confuse yourself now this is what we want to reduce: (81x^4-16) In algebra there is a way to reduce them are you ready for the magical formula?

OpenStudy (anonymous):

Yes!

OpenStudy (anonymous):

This formula is called the difference of squares Before I step further, let me break it down for you To reduce squares, say (16x^2 -4) you would have to square root the coefficients first the square coefficients would be 4 and 2 square rooting x^2 would give you x Whenever you have a subtraction in the brackets you would have to multiply the addition and subtraction versions

OpenStudy (anonymous):

Now comes the formula you will consider (a^2 - b^2) = (a+b)(a-b)

OpenStudy (anonymous):

do you get this so far? let me know if something confuses you

OpenStudy (anonymous):

I think I understand...

OpenStudy (anonymous):

okay, ill give you an example right after this to make sure SO looking back at our example: (16x^2 -4) a^2 = 16 a = 4 b^2 = 4 b = 2 The square root of x^2 is simply x now you make the factor using the formula (16x^2 -4) = (4x -2)(4x+2) you can reduce it to become (16x^2 -4) = 2(2x -1)(2x+1)

OpenStudy (anonymous):

you get that?

OpenStudy (anonymous):

why is b^2=4? and x^2=x? I am sooooo confused. I don't think there's any hope for me getting this tonight! lol

OpenStudy (anonymous):

lol there is Im staying up to make sure

OpenStudy (anonymous):

I understand that in my original problem the answer could be reduced further.

OpenStudy (anonymous):

let's put this aside and go back to our question Maybe it's the numbers that are the same Could probably be confusing you

OpenStudy (anonymous):

So we have this: (81x^4-16) What would be a^2?

OpenStudy (anonymous):

Use the formula i gave you: (a^2 - b^2) = (a+b)(a-b)

OpenStudy (anonymous):

a? I have no idea.

OpenStudy (anonymous):

16

OpenStudy (anonymous):

Look at this side of the formula: (a^2 - b^2) Look at this now: (81x^4-16) Match it up. Hint: Include the x as well.

OpenStudy (anonymous):

a^2 and b^2 are perfect squares

OpenStudy (anonymous):

All you have to do is tell me what a^2 and b^2 are :)

OpenStudy (anonymous):

16?

OpenStudy (anonymous):

what is that? a^2 or b^2 It's one of them :)

OpenStudy (anonymous):

haha you're so mean!

OpenStudy (anonymous):

a

OpenStudy (anonymous):

haha what did i say?

OpenStudy (anonymous):

b^2=4 ;)

OpenStudy (anonymous):

and nopeeee b^2 = 16

OpenStudy (anonymous):

OMG

OpenStudy (anonymous):

(81x^4-16) look at that

OpenStudy (anonymous):

to get b you have to take the square root of b^2

OpenStudy (anonymous):

you know how to square root?

OpenStudy (anonymous):

Yes. But how do you square root a letter with a power?

OpenStudy (anonymous):

you subtract it's exponent But I know what you're thinking b^2 is just a variable squared we want to find b okay :) Want me to run a small example?

OpenStudy (anonymous):

Sure, can't guarantee I'll understand.

OpenStudy (anonymous):

I can :) Say you have an expression as follows: x^2 = 16 Your goal is to square root both sides and find x what would the square root of 16 be?

OpenStudy (anonymous):

4

OpenStudy (anonymous):

Good!! Now what is the square root of x^2? Remember divide the exponents by 2

OpenStudy (anonymous):

16?

OpenStudy (anonymous):

nope i just want the square root of x^2 dont look at 16 look at x^2 you have two sides of the equation x^2 is your left side 16 is on the right side correct?

OpenStudy (anonymous):

Looking at this would help x^2 = 16 Left right

OpenStudy (anonymous):

Tell me. haha

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