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OpenStudy (anonymous):

a truck accelerating at 0.0083 meters/second E covers a distance of 5.8/10E meters. if the trucks mass is 7,000 kilograms, what is the work done to reach this distance

OpenStudy (anonymous):

what do you mean by 5.8/10 E as for the answer ,word done is = force*displacement*cos(theta) here theta = 0 degree force = mass*acceleration i suppose all these data are given in your question

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