A number being successively divided by 3, 5 and 8 leaves remainders 1, 4 and 7 respectively. Find the remainders if the order of divisors be reversed.

Question

anonymous · Answer

6,4,2

loser66 · Answer

I don't understand the question. what does "the order of divisors be reversed" mean?

loser66 · Answer

Let the number is n, then
n = 1 [mod3]
n =4 [mod5]
n= 7 [mod 8]
then? what is next?
@mathmale

anonymous · Answer

A number when successively divided by 3,5,8 leaving remainders 1,4,7 can be written as 3(5(8k+7)+4)+1

=>120k+118

when this number is dived by 8 i.e (120k+118)/8=15k+14 remainder 6
(15k+14)/5=3k+2 remainder 4
(3k+2)/3=k remainder 2
And D) 6,4,2

loser66 · Answer

got it, thank you