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Mathematics 20 Online
OpenStudy (anonymous):

You have a large bag in front of you and randomly pick out one candy. Find P(yellow), the probability that you select a yellow candy. Orange: 0.25, Yellow: ?, Brown: 0.40

OpenStudy (queelius):

When the events are mutually exclusive (that means, only one of them can happen) and exhaustive (one of the events will happen), then P[orange] + P[yellow] + P[brown] = x. What is x?

OpenStudy (anonymous):

x is after the semi colons

OpenStudy (anonymous):

I am trying to find out what x will be for yellow

OpenStudy (queelius):

The probability of *something* happening is 1. Thus, P[orange] + P[yellow] + P[brown] = 1. Now, the rest is algebra.

OpenStudy (queelius):

P[brown] = 1 - (what goes here?)

OpenStudy (queelius):

Errr, P[yellow] = 1 - ?

OpenStudy (anonymous):

do i just add then divide?

OpenStudy (queelius):

Sorry. :)

OpenStudy (queelius):

No division -- we only need to rearrange the equation, P[orange] + P[yellow] + P[brown] = 1. We are solving for P[yellow], so: P[yellow] = 1 - P[orange] - P[brown]

OpenStudy (anonymous):

i have 17 minutes to answer this and like 20 other questions

OpenStudy (anonymous):

so...whats the answer?

OpenStudy (anonymous):

it turned out to be 0.35

OpenStudy (queelius):

Yes, 0.35 looks correct.

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