Question

derivative of (sin(2x))^3? I need the steps, I think my answer is wrong

Answer 1

chain rule is useful in this ... whats your answer?

Answer 2

6sin^2(2x)cos(2x)

Answer 3

maybe I'm doing the chain rule wrong?

Answer 4

(sin(2x))^3

f(g(h))

f^3 = 3f^2 f', but f=sin(g)

f' = cos(g) g', but g=2x

g' = 2

3sin^2(2x) * cos(2x) *2

is right, but can prolly be simplified by some archaic trig rules

Answer 5

s^2 = 1-c^2

6 (1-cos^2(2x)) * cos(2x)

prolly not that route ... sin2x cos2x = 2sin(x/2) maybe?

Answer 6

all depends on whos grading it.

Answer 7

what I have here is 3sin(2x)sin(4x)

Answer 8

that works too

Answer 9

i had my sin2x cos2x a little off in my head :)

Answer 10

ok then, thank you

Answer 11

youre welcome