Question

IIT Jee

Answer 1

@ganeshie8

Answer 2

oh iit prepper!!

Answer 3

keep going

Answer 4

Hmmm r u an iitian ?

Answer 5

sadly no, but i have prepared for one and i think i came through this question once

Answer 6

Actually i was surfing through some IIT Papers as i am giving the exam in 2016 and i saw this problem looked straight forward

Answer 7

okay.. ill guide you

Answer 8

I found the quadratic equation

Answer 9

\[\alpha \beta x ^{2} - (\alpha ^{2}+\beta ^{2})x +\alpha \beta =0 \]

Answer 10

first use \[\alpha ^{3} + \beta ^{3}=(\alpha + \beta)^{3}-3\alpha \beta(\alpha+\beta)\]
\[now, you know values of \alpha ^{3} + \beta ^{3} and (\alpha+\beta)\]
substitute above and get value of
\[\alpha \beta\] ....(1)
now use sum of roots property=(-b/a)=\[\alpha/\beta + \beta/\alpha \]
on taking lcm, \[(\alpha ^{2} + \beta ^{2})/\alpha \beta \] ......(2)
now \[\alpha ^{2} +\beta ^{2} = (\alpha+\beta)^{2} -2\alpha \beta\]
substitute in (1)
put value of \[\alpha+\beta=-p (given \in question)\]
and value of \[\alpha \beta \] from (1) and solve for sum of roots
compare this with (-b/a) of the equations given as option

Answer 11

got it!!!!

Answer 12

yes thank you!