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Mathematics 8 Online
OpenStudy (anonymous):

Help me with matrices? :)

OpenStudy (aravindg):

Question? :)

OpenStudy (anonymous):

OpenStudy (aravindg):

Take all the coefficients and form a 3 x 3 matrix.

OpenStudy (anonymous):

In all honesty i have no idea whats going on in my class im trying to catch up fast:/

OpenStudy (aravindg):

AX=B is the matrix equation. A is coefficient matrix and B is constant term matrix.

OpenStudy (aravindg):

First make a matrix A using the coefficients of x,y,z

OpenStudy (anonymous):

ahhh i think i'm just gunna guess on this one I literally know nothing :p

OpenStudy (aravindg):

Guess? You taking a test?

OpenStudy (anonymous):

It's just a small quiz type thing

OpenStudy (aravindg):

Well getting help during the test is a bad idea. Come back after it and we can do the review!

OpenStudy (anonymous):

It's a quick check so its not a test but thanks anyways! :)

OpenStudy (anonymous):

\[0x+2y+7z\\ -3x-7y+0z\\ 7x+0y-8z\] coefficients are \[0,2,7\\ -3,-7,0\\ 7,0,-8\]

OpenStudy (anonymous):

something like \[ \left[ {\begin{array}{cccc} 0 & 2 &-7\\ -3 & -3 &0 \\ 7 & 0 &-8 \end{array} } \right] \]

OpenStudy (anonymous):

im not sure how you form the 3x3 matrix

OpenStudy (anonymous):

oh wait is that it?

OpenStudy (anonymous):

you need a column vector with the right hand side of the equations

OpenStudy (anonymous):

is that my answer? or does it have to be simplified more?

OpenStudy (anonymous):

that is it, but it is not done you need the column of the answers

OpenStudy (anonymous):

-3 3 3

OpenStudy (anonymous):

not sure how to draw one here

OpenStudy (anonymous):

yeah, like that

OpenStudy (anonymous):

so is that it? thank you for helping me btw :)

OpenStudy (anonymous):

yeah, that's it easy right? yw

OpenStudy (anonymous):

ahhh can you help me with another :)

OpenStudy (anonymous):

sure if i can

OpenStudy (anonymous):

OpenStudy (anonymous):

to hell with matrices this is much easier than that multiply the first equation all the way across by \(3\) and the second one all the way across by \(-2\) you go from \[-3x+2y=10\\ -4x+3y=2\] to \[-9x+6y=30\\ 8x-6y=-4\] then add them up and the \(y\) terms drop out leaving you with \[-x=26\] and so \(x=-26\)

OpenStudy (anonymous):

you good with that? you still need \(y\)

OpenStudy (anonymous):

Yes that was i need to figure out now.. how do i do that do i multiply?

OpenStudy (anonymous):

is it -34???

OpenStudy (anonymous):

replace \(x\) by \(-26\) in either equation for example in the first one you would turn \[-3x+2y=10\] so \[-3\times (-26)+2y=10\] or \[78+2y=10\] and that is easy to solve

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Ahh thank you so much <3 :D

OpenStudy (anonymous):

\[78+2y=10\\ 2y=-68\\ y=-34\] you win yw

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