Can the formula for Magnetic Field Charge be used to calculate the field force in an electric field, using a velocity, field strength, charge and angle from field direction?

A question on my homework has a value of E, q, v and a theta, but I only know one equation for Electric Field force: F=Eq. (?) so... Do I substitute E for B in the magnetic field force equation? Is there another equation for electric?

Any and all help is greatly appreciated! :)

Question

Can the formula for Magnetic Field Charge be used to calculate the field force in an electric field, using a velocity, field strength, charge and angle from field direction?

A question on my homework has a value of E, q, v and a theta, but I only know one equation for Electric Field force: F=Eq. (?) so... Do I substitute E for B in the magnetic field force equation? Is there another equation for electric?

Any and all help is greatly appreciated! :)

aravindg · Answer

I don' think so. Unless you have a region of combined magnetic and electric fields. Then the effective force is given by

$$F=q(E+v \times B)$$

amonoconnor · Answer

So, to find the force on an electron, within an electric field, if I am given a velocity do I ignore it, and simply do Eq?

aravindg · Answer

Hmm...They must be given for a reason. Did you solve F=qE and check the solution?

amonoconnor · Answer

In this case F = 4.806x1@^(-19) N.

amonoconnor · Answer

I can't check my answers against any type of answer key, but I also can not figure out how a velocity plays into electrical fields formulas. We are working with The Right Hand Rule, if that gives any insight on your end. I am supposed to determine the Force acting on the electron with an electric field of 3N/C acting to the right, and an electron moving up at 2m/s.

amonoconnor · Answer

One electron = 1.602x10^(-19) C, and E is a given (3N/C).

aravindg · Answer

The thing that velocity could play a role is about changing the distance. This could vary the Field as it is inversely proportional to distance.

amonoconnor · Answer

Okay, that makes sense. I think, from my end, seeing everything I'm given and knowing what type of field this is, and based on what you've shared, that I just ignore the velocity, and compute using F = Eq... It wouldn't make sense to use the gravitational equation, and I know not of an Electrical equation with velocity... :/

aravindg · Answer

Wait..Can you provide me with the exact question? I think I got something to add.

amonoconnor · Answer

Yes! It is... "The electric field above has magnitude 3.0 N/C. For each of the following particles placed in the field, find (a) the force exerted by the electric field on the particle, and (b) the acceleration of the particle. Be sure to give both magnitude and direction." 
There are 8 different sets of criteria, and number three  (origin of my question)is as follows...                        
"3. An e- moving ⬆️ at 2 m/s."

aravindg · Answer

Is there a figure?

amonoconnor · Answer

Yes, it is a set of horizontal arrows, to the right side of the page, and a smaller directional arrow labeled with an "E", indicating what type of field lines are shown.

aravindg · Answer

So where was theta mentioned?

amonoconnor · Answer

It wasn't, I just know the equation for the force on a particle in a magnetic field [ FsubB = |q|vB(sin(theta)) ], and knew that velocity could be plugged in there, as could an angle, and was guessing it was ninety, from using the Right Hand Rule.

aravindg · Answer

Is it written an electron moving up?

amonoconnor · Answer

Yes, it is an arrow, pointing up.

amonoconnor · Answer

Is it correct to to assume that the velocity is a unneeded piece of information?