A coin is unbalanced such that it comes up tails 55% of the time. In an effort to prove that the coin is unfair, an experimenter flips the coin 50 times. a) what is the probability that the coin comes up tails more than 25 times? b) what is the probability that the coin comes up tails more than 30 times? c) what is the probability that the coin comes up tails exactly 25 times?
@jim_thompson5910 how would I figure this out?
you all figure out that calculator? here is one way to do it http://www.wolframalpha.com/input/?i=%2820+choose+3+%29*%281%2F6%29^3%285%2F6%29^17
yes we did and thanks for that, wolfram is usually a quicker way to compute but it's also handy to know how to do it on a calculator so you can do it on the test
as for this newest one, this is definitely going to be a pain to do by hand
for part a) you have to calculate the binomial probabilities for k = 26, k = 27, k = 28, ..., k = 50 and add them all up the good news is that your calculator supports the binomial cdf function
i thought maybe this was a statistics question, use the normal approximation to the binomial otherwise it is going to be a real drag i am not that good at those problems, so i will be quite now but as i said, my best guess is normal approximation
I guess you could do that, but if you use the normal distribution, you have to use the Continuity Correction Factor
So what do I do? *Sorry OpenStudy crashed and I had to switch computers which required some negotiating*
that's ok
do you know how to use the binomial cdf function?
on your calculator
What's that?
before, we calculated the binomial pdf (basically a single probability) now, we want to calculate a whole bunch of probabilities (from k = 26 to k = 50) and add them up. That gives the binomial cdf
we could do what we did in the last problem, and do k = 26, k = 27, ..., k = 50 but that's very tedious the good news is that there's a much quicker way using a calculator
are you able to find the distribution button?
Where is that? Do I get to it the same way I got to the last one?
let me look at the manual again
are you able to get into stat mode?
Yes
ok go ahead and get into stat mode, then press f5 to bring up the DIST (distribution) menu
Okay, now what?
then select BINM (for binomial)
what do you see after you do this?
There's then the options: Bpd, Bcd, and InvB
ok one sec
do Bcd (Binomial Cumulative Distribution)
the first one would have solved the previous problem in basically one step
Now what?
whats on your screen right now?
the calculator screen
Data: List List: List1 Numtrial: 0 P: 0 Execute
ok for Numtrial, you're going to put in 50 (since there are 50 coin tosses, so 50 trials)
p = 0.55 because this is the probability of landing on tails (for this coin)
Alright
as for the "data" portion, I'm not sure
are you able to change "list" to something else?
I clicked on 'list' and this popped up: Select List No. List [1~26]:
so you can only choose from list1 through list26
I wish there was a way to input a single value (and forget about the list)
Oh! You can change 'Data: List' to 'Data: Variable' and then 'List: List1' changes to 'x: 0' is that helpful?
oh much better
that x would then be 25 (for part a)
it might not give the final answer, but it certainly will help get us there
so try x = 25 Numtrial = 50 p = 0.55 and tell me what you get
Binomial C.D p = 0.28396067
So what that just calculated was P(X <= 25) basically the probabilities for k = 0, k = 1, ..., k = 25
but we want k = 26 on up to k = 50
so we simply subtract from 1 to get 1 - 0.28396067 = 0.71603933
Ohh, so that's a?
yes and do you see why I subtracted from 1?
Yes. So for b, would I do the same thing except with 30 instead of 25 and subtract that number from 1?
exactly
you would use a calculator to compute P(X <= 30) then subtract from 1 to get P( X > 30)
Is 0.19736794 correct?
let me check
I'm getting the same (more or less), nice work
Yay!
to answer part c), you can either use the formula (n C r)*(p)^(k)*(1-p)^(n-k) OR you can use the Bpd portion (instead of the Bcd) of the calculator
Bpd calculates single probabilities Bcd calculates a whole bunch of what Bpd does and adds them all up
oops I meant to say (n C k)*(p)^(k)*(1-p)^(n-k)
would it be 0.08733002?
correct
Awesome! :D
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