Two cards are drawn in succession without replacement from a standard deck of 52 cards. What is the probability that the first card is a spade given that the second card is a diamond? (Round your answer to three decimal places.)
I have an idea on how to do this but i think im messsing up somewhere along the process
are you familiar with bayes theorem?
yes.. that is what I am using, but I cant seem to get the right answer. I dont know what I am doing wrong
alright lets see what we can do.. D = 2nd card is diamond S = 1st card is spade \[P(S | D) = \frac{ P(D|S)P(S) }{ P(D) }\]
so here i think the P(D | S) = (13/52)(13/52) and P(S) = 13/52 but im not quite sure on how to get the P(D)
sorry p(D|S) = (13/52)(13/51)
well i used the other form of baye theorem \[P(S|D) = \frac{ P(D|S)P(S) }{ P(D|S)P(S) + P(D|S')P(S') }\] where \[P(D|S') = {(\frac{ 52-13 }{ 52 })\frac{ 13 }{ 51 } }\] and P(S') = 39/52
ya i was using P(D) = (39/52)(13/51) + (13/52)(13/51)
but it came out as a low number which it feels kinda wrong unless its correct lol
what did you get?
i was getting .250 and it was wrong
i got around 10% assuming did the algebra correctly, i did it fast so idk if i made a mistake or not
let me calculate it again
I got 0.1 = 10% its pretty low so it feels kinda wrong lol
it has to be rounded to 3 decimal places... do you know the next 2 numbers?
its just 0.1, so 0.100
no its not right :(
yea thought so i didnt think it was right but idk what exactly im doing wrong
try 0.255 see if it's right
yes!!! that problem was driving me crazy!
thanks!
Join our real-time social learning platform and learn together with your friends!