Question

Find the first five terms of the given sequence
Please Help
(Sequence in comments)

Answer 1

\[a _{1}=9,a _{n+1}=\frac{ 2a _{n}-2 }{ 2 }\]

Answer 2

a.9, 7, 5, 3, 1
b.9, 16, 14, 12, 10
c.9, 8, 7, 6, 5
d.9, 1, 2, 3, 4

Answer 3

:3

Answer 4

First simplify \[a _{n+1}=\frac{ 2a _{n}-2 }{ 2 }\]

Answer 5

\[a _{n+1}=\frac{ 2a _{n}-2 }{ 2 } = a_n - 1\]

Answer 6

So the next term is just the previous term minus 1.

Answer 7

\[a _{2}=\frac{ 2a _{1}-2 }{2 }\]?

Answer 8

oh so that would make it 9,8,7,6,5?

Answer 9

yes.

Answer 10

Thanks!

Answer 11

You are welcome.

Answer 12

(✌ﾟ∀ﾟ)☞