Evaluate the integral by making the given substitution.
\[\int\limits_{?}^{?}\sec(6x)\tan(6x) dx\] u = 6x
The more detailed the better, I'm trying to get better at trig
well, it will yield to \[\int\limits \sec(u)\tan(u) \frac{ du }{ 6 }\]
well if y = sec(x) then dy/dx = sec(x)tan(x) you don't need a substitution so sec(6x) = 6sec(6x)tan(6x) hope it helps
then it is now easy to integrate. :))
its asking me to use do the given substitution, going around the instructions doesn't get me points :p
you can follow me, then :D
well use @Yttrium version... it uses a substitution and makes sense...
but I'd be asking you're teacher why you would need a substitution for this question
if you still have clarification, feel free to post it here :)
thanks everyone >.<
@campbell_st maybe theire topic is about integration by substitution and they're teacher just though of an example like this. :)
***their
no i get it, i was trying to convert sec to 1/cos and tan to sin/cos before trying to integrate it, it wasn't first nature to realize that the antiderivative is just sec(u)
Alright then. Sudden realization! :D
yeah! exactly haha thanks :)
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