Question

Find the following sum.

Answer 1

\[\frac{ x^2-6x }{ x-3 }+\frac{ 9 }{ x-3 }\]

Answer 2

since denominator is same, just add the numerator
it is a form of whole square
some portion cancels out
you get the answer

Answer 3

\[\frac{ x^2-6x+9 }{ x-3 }\]

Answer 4

\[\frac{ (x-3)(x-3) }{ x-3 }\]
Answer: x-3

Answer 5

excellent!!

Answer 6

thank you! :)