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Mathematics 16 Online
OpenStudy (anonymous):

B. what is the probability of selecting a red marble, setting it aside, and then selecting a blue marble? show your work C. are the answers to parts (A) and (B) the same?

OpenStudy (anonymous):

OpenStudy (anonymous):

@paki

OpenStudy (paki):

little wait, i have problem in my internet connection.... :-(

OpenStudy (sidsiddhartha):

firstly there are 4 red marbles and total 16 marbels is'nt it

OpenStudy (sidsiddhartha):

so prob of selecting red is=4/116=1/4

OpenStudy (sidsiddhartha):

and prob of selecting a blue is=7/16 do u get it

OpenStudy (anonymous):

yea and then you multiply and get 7/67

OpenStudy (anonymous):

so it that the anwser for b

OpenStudy (sidsiddhartha):

so prob of selecting red then a blue is=prob of selecting red*prob selecting blue =(4/16)*(7/16)

OpenStudy (anonymous):

so the answer would be 7/64

OpenStudy (sidsiddhartha):

now ur selecting a red marble, setting it aside, and then selecting a blue marble is'nt it?

OpenStudy (anonymous):

yea

OpenStudy (sidsiddhartha):

so prob of selecting red=4/16 now one of the red is removed now prob of selecting blue=(blue marbels)/(all marbels except the specific red which has been removed)=7/15 it is okay??

OpenStudy (anonymous):

yea i got it thanks

OpenStudy (sidsiddhartha):

no its not ends here

OpenStudy (sidsiddhartha):

now ur required prob=(4/16)*(7/15)=7/60

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