B. what is the probability of selecting a red marble, setting it aside, and then selecting a blue marble? show your work
C. are the answers to parts (A) and (B) the same?
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OpenStudy (anonymous):
OpenStudy (anonymous):
@paki
OpenStudy (paki):
little wait, i have problem in my internet connection.... :-(
OpenStudy (sidsiddhartha):
firstly there are 4 red marbles and total 16 marbels is'nt it
OpenStudy (sidsiddhartha):
so prob of selecting red is=4/116=1/4
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OpenStudy (sidsiddhartha):
and prob of selecting a blue is=7/16
do u get it
OpenStudy (anonymous):
yea and then you multiply and get 7/67
OpenStudy (anonymous):
so it that the anwser for b
OpenStudy (sidsiddhartha):
so prob of selecting red then a blue is=prob of selecting red*prob selecting blue
=(4/16)*(7/16)
OpenStudy (anonymous):
so the answer would be 7/64
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OpenStudy (sidsiddhartha):
now ur selecting a red marble, setting it aside, and then selecting a blue marble is'nt it?
OpenStudy (anonymous):
yea
OpenStudy (sidsiddhartha):
so prob of selecting red=4/16
now one of the red is removed
now prob of selecting blue=(blue marbels)/(all marbels except the specific red which has been removed)=7/15
it is okay??
OpenStudy (anonymous):
yea i got it thanks
OpenStudy (sidsiddhartha):
no its not ends here
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