@hartnn
Hi Lui :)
Yes I still need help please >.< Last one closed.. http://prntscr.com/3ekqa9 But you sure a u-sub would work?
yes! whenever there is a linear expression within \(\large \sqrt[n]{linear}\) we substitute u = linear expression
after the substitution, you just need to separate the denominator :)
did you try it ?
OS is still lagging for me, sorry. And I have never done a problem like this before so I don't really follow :/
ok, never substituted in an integral ?? we need to replace every 'x' by a 'u' so wherever you see x, replace it by 'u-9' also, find du
u = x+9 thats why x = u-9 and du =...?
I've done sub before.. \(u=x+9\) and \(du=dx\) Leaving us with \(\Large \int \frac{x}{\sqrt{u}} du\)?
not actually, as i said, we need to replace EVERY 'x' by a u after there substitution, there should not by any 'x' left.
OH, now I see what you mean! \(\Large \int \frac{u-9}{\sqrt[4]{u}} du\)?
OS is switching the replies .-.
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