Question

Divide. Assume the denominator does not equal zero.

12x^2y-6xy+4x^2/2xy

Answer 1

You separate it into two:
\(\Large \frac{12x^2y}{2xy}-\frac{6xy}{2xy}+\frac{4x^2}{2xy}\)
Now simplify individually.

Answer 2

how do you simplify it?

Answer 3

It can be separated farther if you need it:
\[\LARGE \frac{12x^2y}{2xy} =\frac{12}{2}*\frac{x^2}{x}*\frac{y}{y}\]
Do you know how to divide variables and powers?

Answer 4

no :/ im new at this stuff..

Answer 5

Rule being, say we have something like \(\Large \frac{x^5}{x^2}\) we simplify by subtratcing exponents like such \(\Large x^{5-2}\), leaving us with \(\Large \frac{x^5}{x^2}=x^3\). Make sense?

Answer 6

yes :)

Answer 7

so 12x^2y/2xy would be 12xy/y? or just 12x?

Answer 8

Close, you forgot that 2 under 12, just do regular division with that. And the y/y cancel leaving a 1. So it'll just be 6x.