Question

-x+2y=3
x^2+y=3
How do I solve with substitution?

Answer 1

Add the 2 equations.

Answer 2

you probably didn't mean x^2.

Answer 3

I ment how do I deal with the x squared

Answer 4

Or if you did, multiply the second equation by -2, and then add.

Answer 5

-x+2y=3
x^2+y=3 ---> times -2 ---> -2x²-2y=-6

now

-x+2y=3
-2x²-2y=-6
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Answer 6

Isolate one of the variables from one of the equations then sub it into the other.

Answer 7

basically.

Answer 8

So can you show us some work?

Answer 9

@bannannna

Answer 10

I got to -2x^2-x+3=0

Answer 11

Yeah usually when you ask Op to show work, they leave. So at that point I leave as well, because I know they aren't willing to learn.

Answer 12

I didn't leave just app doesn't show me typing

Answer 13

We have two equations -x + 2y = 3 & x^2 + y = 3 , So you can use any substitution,
So here we solve second equation x^2 + y = 3 for y , so we will get y=3 - x^2.
Now plug this value y = 3-x^2 in first equation & solve for x,
That is - x + 2(3-x^2) =3 , => -x + 6 - 2x^2=3, => -2x^2 -x+3=0 now use quadratic formula & solve for x then plug that value of x in any equation you will get y

Answer 14

Ohh I see

Answer 15

I know what to do now thanks

Answer 16

you are welcome :)