Question

geometric sequencing

Answer 1

what about it?

Answer 2

Find the sum of the geometric sequence.

\[1, \frac{ 1 }{ 2 }, \frac{ 1 }{ 4 }, \frac{ 1 }{ 8 }, \frac{ 1 }{ 16 } \]

Answer 3

i get that the pattern is multiplying it by 1/2 but i dont understand how to find the sum

Answer 4

I think there's a formula for adding geometric sequences, isn't there?

Answer 5

yeah this website lists it
http://www.mathsisfun.com/algebra/sequences-sums-geometric.html
but it dosent tell me how to get to the sum :c

Answer 6

Just use this formula: http://prntscr.com/3eov4p

Answer 7

i think @halorazer thinks your a girl cuz he just messaged me that you want the d...... but he seems to think your a girl

Answer 8

okay so this is the equation but how do i know whats what? .-. @Luigi0210

Answer 9

It's true, Luigi wants the D.

Answer 10

Anyways, for your question. Can you identify whether or not the sequence is finite or infinite?

Answer 11

lol i don't need your help @halorazer your just a nuisance, thus i bid you farewell

Answer 12

Oh, okay. Let's call names shall we.

Answer 13

-.- this is exactly why i dont want you on my question...... now @Luigi0210 how do you tell the different parts apart? .-.

Answer 14

Bro, please ;)

And let him help. I have something to do in the meanwhile ._.

Answer 15

Brofist, Luigi. :3

Answer 16

So do tell me, what is the common ratio between values?

Answer 17

i hate you ಠ╭╮ಠ

Answer 18

Eh, you're not the first. I'm helping you though, so.

Answer 19

yay your back! ✧･ﾟ:*✧･ﾟ:* \(◕‿◕✿)/ *:･ﾟ✧*:･ﾟ✧

Answer 20

I was talking to the female companion, am sorri.

Answer 21

Can you pls read dis http://www.urbandictionary.com/define.php?term=suck%20my%20ass
I do believe what I said was "suck my retrice" Asses go in, therefore you cannot suck it.

Answer 22

Sum of the first "n" terms of a geometric series: \[a\frac{1-r^n}{1-r}\]Sum of an infinite geometric series: \[\frac{a}{1-r}\]where a is the first term
r is the common ratio.
n is the number of terms.

Answer 23

thank you @ranga
@halorazer ~mabey you could learn a thing or two from helpful people such as this -.-

Answer 24

You are welcome.

Answer 25

okay so it would be \[1\frac{ 1-\frac{ 1 }{ 2 }^{5} }{ 1-\frac{ 1 }{ 2 } }\]

Answer 26

It's a bit difficult to help someone that won't let someone help them. And that's why I get medals on 86% of my answers. :)

Answer 27

no you only get medals from the people you arnt complete bicth to

Answer 28

Which is erryone. It's funny, because I treat everyone the same and no one else complains. Is something wrong?

Answer 29

yeah, with you mabey

Answer 30

Yes, that would be the sum of the 5 terms of the given geometric sequence. Just need to simplify it.

FYI: People have the option to block others by positioning the mouse over the person's name, and clicking on 'Block User'.

Answer 31

It's a fancy button isn't it. She'd much rather insult me than block me.

Answer 32

youd much rather have sex with me than block me .-. youve said so on several occasions

Answer 33

I have never blocked someone on here. I believe in peaceful resolutions. You, however, are more than welcome to block me. :3 I'm sorry you feel the need to do so.

Answer 34

okay so simplifying it, the 1s would cancel out and leave you with \[1\frac{ \frac{ 1 }{ 2 }^5 }{ \frac{ 1 }{ 2 } }\] but 1/2 ^5 is 1/32.... so then its

Answer 35

It is \[\Large 1\frac{ 1 - \frac{ 1 }{ 2 }^5 }{ \frac{ 1 }{ 2 } }\]

Answer 36

.-. \[1 \frac{ 1-\frac{ 1 }{ 32 } }{ \frac{ 1 }{ 2 } }\]

Answer 37

simplify further. 1 - 1/32 = ?
dividing by 1/2 is same as multiplying by 2.

Answer 38

it would be -31/32?

Answer 39

1 - 1/32 = +31/32
divide 31/32 by 1/2 or
multiply 31/32 * 2/1 = 31/16

Answer 40

which would equal 2 and 15/16 c:

Answer 41

You can verify the sum is correct by simply adding the 5 terms:
1 + 1/2 + 1/4 + 1/8 + 1/16 = 16/16 + 8/16 + 4/16 + 2/16 + 1/16 =
(16+8+4+2+1)/16 = 31/16

Answer 42

.-. but 2 15/16 isnt one of my answers, infact its nowhere near any of my answers

Answer 43

16 goes into 31 just once (not 2).

Answer 44

yeah but in front of the whole problem there was a 1

Answer 45

That 1 after you plug into the formula is a multiplication and not an addition.

Answer 46

It is \[a * \frac{1-r^n}{1-r} = 1 * \frac{1-1/2^n}{1-1/2} \]

Answer 47

You don't see 1 & 15/16 or 31 / 16 among the answer choices?

Answer 48

no.... Find the sum of the geometric sequence.

1, one divided by two, one divided by four, one divided by eight, one divided by sixteen

one divided by twelve

93

negative one divided by forty eight

thirty one divided by sixteen

Answer 49

last choice.

Answer 50

oh okay c: thank you

Answer 51

yw.