Question

I could use some help with these

Answer 1

do you know what they mean? for example, do you know what
\[\sum_{i=1}^64i-1\] means?

Answer 2

Well, I did at one point

Answer 3

since underneath the big "sigma" it says \(i=1\) that means first replace \(i\) by \(1\)
in this case you would get \(4\times 1-1=3\)
then put a plus sign
then replace \(i\) by \(2\) and get \(4\times 2-1=7\) so now we have
\[3+7\]for the first two terms

Answer 4

then replace \(i\) by \(3\) and get \(4\times 3-1=11\) and so on
when you add you would get
\[\sum_{i=1}^6 4i-1=3+7+11+15+19+23\]

Answer 5

obviously that is not the right answer because that isn't what you were given at the beginning

Answer 6

What does the 6 do in the equation?

Answer 7

it tells you when to stop
in this case you would stop at \(i=6\)

Answer 8

that is why when i wrote
\[\sum_{i=1}^6 4i-1=3+7+11+15+19+23\] there were six numbers

Answer 9

I got it now, thanks