Question

A bag of tiles contains 5 A's, 3 B's, 2 C's. what is the probability of picking ABC in order in three draws from the bag, without replacement?

Answer 1

someone help plzzzz

Answer 2

For the first pick, what is the probbaility of picking an A?

Answer 3

i don't know how to do that

Answer 4

Ok.
The probability of an event happening is the number of ways the event can happen divided by the total number of ways all events can happen.

Answer 5

In this case, all events are picking one of 10 tiles.
The total number of all events happening is, therefore, 10.
Ok?

Answer 6

is picking A is 5/30

Answer 7

Correct.

Answer 8

Once an A has been picked, how many tiles are left?

Answer 9

okay so i do the same thing for all of them and then just multiply them together the fraction

Answer 10

Yes, but the total number of total events changes each time.
Once the A was picked on the first pick, since there is no replacement, there are how many tiles left for the second pick?

Answer 11

29

Answer 12

oh no there will be 25

Answer 13

I think you mean 9.
There were 5 + 3 + 2 tiles = 10 tiles.
An A was taken out.
There are now 10 - 1 = 9 tiles for the second pick.

Answer 14

yeah you are right

Answer 15

then picking A is 5/10 right??

Answer 16

Yes, for the first pick, the probability of picking an A is 5/10.
For the second pick, you want a B out of 9 tiles. How many B's are there?

Answer 17

3 B's so 3/9

Answer 18

Correct.
Now for the third pick, there are only 8 tiles left.
How many C's are there?

Answer 19

2 C's so 2/8

Answer 20

Correct.
All these fractions can be simplified.
To find the answer, multiply them together.

Answer 21

so is the answer 1/24

Answer 22

5\10 * 3/9 * 2/8 =
= 1/2 * 1/3 * 1/4
= 1/24

You are correct.

Answer 23

@ mathstudent55 thank you so much

Answer 24

You are very welcome.