Please help me solve for X in terms of pi. 2pi-x=5pi/3
\[2\pi -x = \frac{5}{3}\pi\] I would start by multiplying each side by 3 to get rid of the fraction. Then add \(x\) to each side and see if you can finish from there...
when i multiply the other side by 3, would it be 2pi-x+3?
or would it be 6pi-x? @whpalmer4
\[3(2\pi-x) = 3*2\pi - 3*x = 6\pi -3x\] Treat \(\pi\) just like you would a variable, although you mistreated the variable here :-)
would 6pi-3x be my answer or would i have to reduce the 3 and the 6?
I would have just isolated the x first.
I would also, but my experience with OS users is that one can't count on their fraction manipulation skills
\(2\pi -x = \frac{5}{3}\pi\) \(2\pi - \frac{5}{3} = x\) I'm confident with @ali1029 skills. I've seen it on display
Ugh, forgot the \(\pi\)
does it make a difference if the problem is actually \[2\pi-x=\frac{5\pi}{3}\] ?
\(2\pi - \frac{5\pi}{3} = x\)
\(2\pi = \frac{6\pi}{3}\) So \(\frac{6\pi}{3} - \frac{5\pi}{3} = x\)
The given problem is \[2\pi-x=\frac{5\pi}{3}\]
@ali1029 no, it makes no difference: \[\frac{5}{3}\pi = \frac{5\pi}{3}\]
oh okay, just wanted to make sure! :p
so wouldd the final answer be 6pi-3x or would i turn that into a fraction?
@ali1029, did you miss what I wrote above?
I'm sorry, let me check!
so x = pi/3?
\[2\pi -x = \frac{5\pi}{3}\]\[6\pi - 3x = 5\pi\]\[6\pi-5\pi = 3x\]\[\pi = 3x\]\[x=\frac{\pi}{3}\]
Correct.
thank you both for your help!! :)
If you see an easier way to isolate x, you should do so, then simplify from there.
Join our real-time social learning platform and learn together with your friends!