Graph
At which point is g′′< g′< g
g is original equation, g' = derivative, g'' = second derivative
graph is y = gx
@theEric
I am terrible at reading graphs lol.
@loser66 Can you read this one?
Hi again! \(g(x)\) is the function's value at \(x\) \(g'(x)\) is the slope of the function at \(x\) \(g''(x)\) is the concavity of the function at \(x\) If \(g''(x)\) is the least, maybe we can look at the most negative concavity. That would be a good point to check out. Which point is that?
@IDKwut
I am not sure how that applies onto the graph??
Well I understand what you said, I just don't see how so and so can be less than this or that (referring the the g function)
The most negative concavity... let's see. It would be e, no?
Nope! When you look at concavity, you look at the curve. So negative is curving down. Most negative would me most curling down.
@Loser66 I think that this graph problem is more for critically thinking about just the meanings of the derivatives. We can guess a function that applies, and that a valid way to look at it too. But we shouldn't apply a specific case to describe a general one. And, most importantly, I think this is an exercise in understanding derivatives.
Then it will be d? or c
This is a more legitamate proof! It is point B! Do you see what I mean? It curls down, and it's the most curvy.
legitimate*
I hate concavity -.- lol. It's so hard to determine sometimes :( So b is the answer?
B is the most negative \(g''\), so it's a good start! Lets see how it goes. I hope you learn concavity! :) When you get a chance, draw any random function and I'll make the concavity. Then I'll make one, and you can mark it! If you want. So, at point B, what is \(g'\) equal to or about equal to?
the slope
Yep! That's what it is! What does the slope look like it might be at that point?
decreasing... lol
Examples:|dw:1398828794031:dw|
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