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when n=14,206 & 957 show that sigma(n)=sigma(n+1)
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\[\sigma(14)=\sigma(2*7)=24=\sigma(3*5)=\sigma(15)\]
is it 2*7 because that is the prime factorization? then i assume you would \[2^2-1/2-1*7^2-1/7-1 \] which is 8? not 24
\(\sigma(14) = \sigma(2) \sigma(7) = (1+2)(1+7) = 24\)
oh okay so you take sigma of each individual prime factor
and how does that equal to (3*5)?
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yes cuz \(\sigma\) is a multiplicative function : \(\sigma(ab) = \sigma(a) \sigma(b)\)
im sorry one more question how is that equal to 3*5?
\(\sigma(15) = \sigma(3) \sigma(5) = (1+3)(1+5) = 24\)
okay got it thanks!
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