What is a sketch of one cycle of y=4 sin 2theta? I have no idea how to do this. :'( Will post a pic of the graph in the comments.
\[y = A \sin(Bx)\] A is amplitude which tell you the max/min of graph B is related to period --> period = 2pi/B the period tells you the length of 1 cycle
thats the graph for y=2sin4theta
The graph I posted? That's what it gave with the question..
the pattern for sine is start at (0,0), then to max, back to 0, then to min, back to 0 the length in between each of these points will be period/4
@sarah1017 , why would it provide a graph of the answer when you are asked to sketch the graph yourself?? is it a multiple choice question?
even more curious why is it the wrong graph? unless she got dyslexic for a second.
This is a find the errors thing. It gives me a question and someones work along with it. I need to identify and state their error and then resolve the problem. Usually when they give a graph it goes with the question, not the answer. I post a picture of the whole thing.
well. look at what cow posted about the amplitude and period of a trig function. and examine the graph. what do you think.
b=0.21? This stuff confuses me.. I got the amplitude which is 2.
I think the 0.21 is the period but I am not sure. Ugh
well you see the period is pi/2 so 2pi/b is period also. you can set them equal to each other and solve for b
what? no the period = 2pi/B = 2pi/2 = pi @lonnie455rich the graph provided is wrong, she has to fix the error
pi/2 is the period in the graph.
what i said is pi/2=2pi/b solve for b.
@sarah1017 , this is easy, just look at the function the number in front of sine is "a" amplitude the number inside the sine is "b" --> y = a sin(bx)
my point is. if you find b in the graph. you can realize the difference in b from the original function to the graph.
oh i see sorry i didn't follow
there is a disclaimer in my profile lol
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