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Mathematics 12 Online
OpenStudy (anonymous):

Simplify x/12x+x^2

OpenStudy (anonymous):

I'm not sure if this is your equation, but if\[\frac{ x }{ 12x+x^2 }\]is what you're asking then what you have to do is pull an X out of the denominator, so you get\[\frac{ x }{ x(12+x) }\]and by noticing that you have\[\frac{ x }{ x }=1\]your equation in the most simplest way can be expressed as\[\frac{ 1 }{ 12+x }\]

OpenStudy (anonymous):

thank you so so much! can you help me with a couple more? @Embryo

OpenStudy (anonymous):

sure thing, ask away

OpenStudy (anonymous):

Simplify \[8x ^{4} \over x ^{3}+7x ^{4}\]

OpenStudy (anonymous):

so we have the same concept as before, let us focus on the denominator\[x^3+7x^4\]notice that both of the terms have a common factor, being that they both have an\[x^3\]so if you take that out, you'll be left with\[x^3(1+7x)\]as the denominator of your fraction, now lets look at the numerator\[8x^4\]same thing as the denominator, we can pull out\[x^3\]from it, giving u\[8x(x^3)\]now combine what we've done to get\[\frac{ 8x(x^3) }{ x^3(1+7x) }\]again we have a common term on both the top and bottom, so they cancel eachother out, and your final answer becomes\[\frac{ 8x }{ 1+7x }\]

OpenStudy (anonymous):

I can't thank you enough! @Embryo

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