What is the amplitude, period, and phase shift of f(x) = −3 cos(4x + π) + 6?
If f(x) is \[f(x)=A \cos (Bx+C)+D\] where |A| is the amplitude The period is \[T=\frac{2 \pi}{B}\] The phase shift is \[\frac{C}{B}\] and the 'y' shift is D
These are my options: amplitude = 3; period = pi over two; phase shift: x = negative pi over four amplitude = −3; period = pi over two; phase shift: x = pi over four amplitude = −3; period = negative pi over two; phase shift: x = negative pi over four amplitude = 3; period = 2π; phase shift: x = negative pi over four Would it be the second one?
In the general equation that I gave above, |A| is the amplitude. So what does |-3| equal?
-3 = A ?
Not really. |-x| = x So |-3| = ?
Oh, -3 = 3 ?
Well, |-3| = 3. So the amplitude is 3. Therefore the second and third choices can be eliminated.
Oh I see. So, D doesn't look right; it would be A?
Why do you say that D doesn't look right? Hint: Find the period.
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