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Mathematics 12 Online
OpenStudy (anonymous):

What is the amplitude, period, and phase shift of f(x) = −3 cos(4x + π) + 6?

OpenStudy (kropot72):

If f(x) is \[f(x)=A \cos (Bx+C)+D\] where |A| is the amplitude The period is \[T=\frac{2 \pi}{B}\] The phase shift is \[\frac{C}{B}\] and the 'y' shift is D

OpenStudy (anonymous):

These are my options: amplitude = 3; period = pi over two; phase shift: x = negative pi over four amplitude = −3; period = pi over two; phase shift: x = pi over four amplitude = −3; period = negative pi over two; phase shift: x = negative pi over four amplitude = 3; period = 2π; phase shift: x = negative pi over four Would it be the second one?

OpenStudy (kropot72):

In the general equation that I gave above, |A| is the amplitude. So what does |-3| equal?

OpenStudy (anonymous):

-3 = A ?

OpenStudy (kropot72):

Not really. |-x| = x So |-3| = ?

OpenStudy (anonymous):

Oh, -3 = 3 ?

OpenStudy (kropot72):

Well, |-3| = 3. So the amplitude is 3. Therefore the second and third choices can be eliminated.

OpenStudy (anonymous):

Oh I see. So, D doesn't look right; it would be A?

OpenStudy (kropot72):

Why do you say that D doesn't look right? Hint: Find the period.

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