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Mathematics 13 Online
OpenStudy (staceyg):

Which graph represents y = |x| -2

OpenStudy (anonymous):

what graph

OpenStudy (staceyg):

Oh sorry hold on I'll post them.

OpenStudy (staceyg):

@algebra1squared

OpenStudy (anonymous):

i'm sorry to say that we can't view the images, as we don't have accounts on that website, or at least most of us probably don't, so instead, give me a minute to make a graph and you can compare it with the ones you have

OpenStudy (staceyg):

Alright thanks. I appreciate it.

OpenStudy (anonymous):

and here you are

OpenStudy (staceyg):

Thanks so much! Could you help with another one?

OpenStudy (anonymous):

sure thing, go ahead and ask

OpenStudy (staceyg):

alright what would a graph for y=-|x-4| look like?

OpenStudy (anonymous):

alrighty, let me start by going over something nice to remember about graphs, in general, they will take the form of\[Y=mx+b\]remember that m is the slope, and if m is negative, then the graph will be pointing downwards, or in other words, it will be increasing in the opposite direction, b is the y-intercept that the graph will cross, meaning that you know for sure that your graph will go through the point (0,b) now for absolute value functions, and any function where your x is surrounded by parenthesis, they will take the form of\[Y=m\left| x-h \right|+k\]where h will tell you if the graph is shifted to the right (positive) or to the left (negative) and k is again, your y-intercept, also again, if m is negative, the graph faces the opposite direction (downward in this case)

OpenStudy (anonymous):

so, from what i've just told you, what can you tell me about the differences between your function\[Y=-\left| x-4 \right|\]and the original graph of\[Y= \left| x \right|\]

OpenStudy (staceyg):

-4?

OpenStudy (anonymous):

not quite, notice that the equation for a general absolute value graph i gave you was\[Y=m \left| x-h \right|+k\]the h is being subtracted from x, that means that in your case, your graph is being shifted 4 units to the right, another way to look at it is to only look at that part of the equation and set it equal to zero\[x-4=0\]then you solve for x and that tells you how the graph shifts on the x-axis now since you have a negative in front of the absolute value, that means your graph will be opening downward

OpenStudy (staceyg):

Would it be the same graph that you showed me before but one unit down?

OpenStudy (anonymous):

the graph you get should look like this

OpenStudy (anonymous):

something you should really remember, is what the original graph of\[Y=\left| x \right|\]looks like, and here's a picture of it all you're doing is moving this graph based on the differences in the equation you are given and the ideas that i stated in previous posts

OpenStudy (staceyg):

Oh my god. I get it now. I feel so dumb. Thanks for everything!

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