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Mathematics 8 Online
OpenStudy (anonymous):

Write the complex number in trigonometric form r(cos theta + i sin theta), with theta in the interval 0-360 degree -7 +7i*(square root 3) i got tan(theta)= - square root 3 so theta has to be 120 or 300 degree but why we use only 120?

OpenStudy (anonymous):

@zepdrix

zepdrix (zepdrix):

Because if you look back at your components... The real component (x) is negative, and the complex component (y) is positive, which puts us in quadrant 2, yes?

zepdrix (zepdrix):

Looks like you found the correct angles! Just relate them back to your complex value to see which angle will actually work for you.

zepdrix (zepdrix):

And I meant imaginary component (y)* the whole thing is complex, I shouldn't have called it that hehe

OpenStudy (anonymous):

hmmmm

zepdrix (zepdrix):

confused? :o

OpenStudy (anonymous):

im just wondering why dont we use the 300 angle lol

OpenStudy (anonymous):

oh ok gotcha

OpenStudy (anonymous):

x= r cos theta y= r sin theta so they need to be in QII

zepdrix (zepdrix):

|dw:1398837790798:dw|Yah, we're in quadrant 2 based on the components we were given. The reason we came up with two angles is because information is lost when you use this:\[\Large\rm \arctan \frac{y}{x}=\theta\]See how the y and x are just kinda smashed together? It doesn't tell us which one was negative, the y or x, when we combine them in this relationship. So it gave us the two possible angles, x negative, y positive produced 120, x positive, y negative produced 300.

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