the weight w of a man can be known from his height h by the relation w = 5h^2+2h where w is in grams and h in centimeters. The error in measuring his height is 0.3 cm. Calculate the approximate error in weight when his height is measured to be 168 cm.
Two general approaches. The first approach is to just solve: max{|w(h+e)-w(h)|,|w(h-e)-w(h)|}. This gives 5e^2+2e(5h+1). Let h=168 and e=0.3, and you have your answer. The solution they are more likely interested in is based on calculus. First, what is the rate of change of w with respect to h? 10h+2. Now, construct a linear approximation of the function, w(h), near h*: w(h) ~ w(h*) + w'(h*)(h-h*). We are given that |h-h*|=0.3, and h*=168. We only care about the output of w'(h*)(h-h*)... So, the solution is: w'(168)(0.3)
is w' = dw/dh ? the answer given is 504.6 grams @queelius
Yes, w' is dw/dh, I apologize for not making that clearer. (10(168)+2)(3/10)=3*168+6/10=504.6
could anyone explain it a little more clearly??
i don't understand how the error is propagating from h to w
the weight equation is quadratic so simple h error will result in a quadratic weight error...
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