Solve the equation |k+7|=3
okay well now take off the absolute value now that it is already isolated and treat it like if it was a normal equation. try it :)
k+7= 3 and k+7=-3 solve now
just like @paki said
to find out put both the negative and positive forms to see if it is valid/true or false
OH okay so, if I subtract 7 from there that'll give me -4 right?
yup -4.... and what about the other equation...
That one is -10 i think.
good :)
yeah -10 is rite...
So the over all answer is (-10,-4) right?
you are genius @SparkyTheWolf
so it is -10 and-4 :)
i agree @paki
Okay I understand =-3, but I have others that I need help on also sadly =-(
post here...
go ahead close this question first
openstudy really doesn't allow many questions in one post, im only enforcing the law but if you dont want to its fine im nice
yup agree
4-3|n+2|>1 Which conjunction or dis junction evaluate the open sentence?
Oh...I really don't know how...I'm kinda new to this
hey @paki how are you answer 50 mil questions at a time i just realized right now. SO COOL
oh easy you know how where it says answer a question and then you posted it underneath it, it says close and bump just click close
Oh...I'll close it after we solve this one if that is alright.
3 at the same time
@paki
um, can you help me with my other question?
yeah
well what is a junction or dis junction do you know what it is
Disjunction, it made me put a space between the two.
4-3|n+2|>1 1 | n+2 | >1 |n+2|>1/1 |n+2|>1 solve now
well A "logical disjunction" simply means : " or " so; "A ∨ B " is read as "A or B ". Such a disjunction is false if both A and B are false. So, the result would be true if one or more operands are true. It would only be false if both or all it's operands are false. A "logical conjunction" simply means "and" so; the symbol is an inverted "v" " A (inverted v) B " are read as " A and B " . The conjunction would only be true if and only if both operands are true, otherwise it would be false. okay: properties under the conjunctions are: 1. "Associativity": the order of operations does not matter as long as the sequence of the operands is not changed. Eventhough parenthesis are changed, operands will still act the same. ex: (5+1) +5 = 5+ (1+5) 2. "Commutativity": to the ability to change the order of something without changing the end result. ex: 3 + 5 = 5 + 3 for addition; 5*3 = 3*5 for multiplication 3. "Distributivity": uses the "dristibutive law" ex: 5( 2 + 3) = (5*2) + (5*3) 4. "Idempotence": multiple applications of that operation will yield the same result. unary operations: - the absolute value operation is a unary operation on the real numbers - the opposite operation (-x) on the real numbers - the power operations (squaring, cubing, etc) on the real numbers - the factorial operation on the real numbers - the trigonometric functions (sin x, cos x, tan x, cot x, csc x, sec x) on the real numbers - the natural logarithm (ln x) on the real numbers - the logarithm of base 10 (log x) on the real numbers - logical negation on truth values These are examples of unary operations, and could be subject to "Idempotence" 5. "Monotonic" - actually these are used mostly for calculus..
but @paki just simpled it out hehe all that writing
|n+2|>1 Okay so I subtract 2 with 1 and got negative -1.
|n|=-1?
yes and that means that the absolute value must be bigger than the -2
i mean -1
it can't really equal remember it is an inequality
Okay so it'll look like this |n|>-1
or n+2>-1
well actually its better n+2>-1
Okay, that all I needed help on =-3 thanks
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