Question

I'm trying to check my answers.

Sodium Hydroxide is formed when sodium oxide reacts with water. Na2O + H2O -->2NaOH

a) Calculate the grams of sodium hydroxide formed when 2.24 moles of sodium oxide react with water. My answer: 179.2 grams NaOH
b) What mass of water (in centigrams) is needed to react with 0.216 mol of sodium oxide? My answer: 468 centigrams H2O

Answer 1

First part is right
Second part im getting this
ratio between Na2O and H2O is 1:1 so H2O's mole will be same =0.216 mol
mole= mass / Mr
mass= mole*Mr
=0.126*18
=3.888 g
convert to centigrams= 388.8 centigrams
I don't know though, maybe you are right and im wrong
:)