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OCW Scholar - Physics I: Classical Mechanics 11 Online
OpenStudy (anonymous):

When 2.0 A of current moves across a 1.0 MΩ resistor, then what is the drop in voltage (V) across the resistor?

OpenStudy (fifciol):

$$V=iR$$

OpenStudy (anonymous):

so it would be 2, right?

OpenStudy (fifciol):

You have to be more precise. What is the unit of voltage in SI units?

OpenStudy (anonymous):

what about the practical source ,draws 2A for 1M ohm

OpenStudy (anonymous):

If you have 1MΩ (Mega ohm), you have \[1.10^{6}Ω\] Then, 2A . 1MΩ = \[2.10^{6}V\]

OpenStudy (anonymous):

apply V=iR (ohm's law) => 2A x1MΩ = 2 MV is the answer

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