Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

Functions and slope

OpenStudy (anonymous):

Graph the linear function: y=1/3x-4

OpenStudy (anonymous):

@vzfreakz XD

OpenStudy (aravindg):

Cam you say what is the y intercept?

OpenStudy (anonymous):

No... Well, I'm not sure how to find it- or what it is

OpenStudy (aravindg):

http://www.mathsisfun.com/equation_of_line.html

OpenStudy (anonymous):

Did he answer your question?

OpenStudy (anonymous):

Well, it helped, but not fully.

OpenStudy (aravindg):

I suppose you understand what is y intercept now.

OpenStudy (anonymous):

XD I'll give it a try.

OpenStudy (aravindg):

Good :)

OpenStudy (anonymous):

Whoa a mod! Nice to meet you Mr.Mod!

OpenStudy (anonymous):

:P hahaha. He's the awesomest! C:

OpenStudy (anonymous):

"y-intercept. Graph y=ƒ(x) with the x-axis as the horizontal axis and the y-axis as the vertical axis. The y-intercept of ƒ(x) is indicated by the red dot at (x=0, y=1)"

OpenStudy (aravindg):

Nice to meet you too :)

OpenStudy (anonymous):

Sorry but this is irrelevant.. How did you become a moderator here?

OpenStudy (aravindg):

The admins select you if you are found mature enough with a good conduct. Okay let's get back to helping!

OpenStudy (anonymous):

:P lol. Hey I think I'm kinda understandin'. XD

OpenStudy (anonymous):

Thats a video explaining slopes and the y intercept stuff

OpenStudy (anonymous):

oh thanks @Gator153760 :) much appreciated.

OpenStudy (anonymous):

Dang he is cool haha

OpenStudy (anonymous):

lol ikr :} lol

OpenStudy (anonymous):

You should be good to go! And they have more videos on the side bar

OpenStudy (anonymous):

Good luck!

OpenStudy (anonymous):

:D Thanks for helpin'! :D

OpenStudy (anonymous):

Oh, and is the answer B?

OpenStudy (aravindg):

Just to add: There is a good method to approach graph problems like this. If equation is y=mx+b Put x=0 and solve for y. The value of y gives u y intercept(ie the location on y axis where the line cuts it) y=mx+b Put x=0 y=b So (0,b) is the y intercept. To find x intercept we can follow a similar method. Put y=0 and solve for x. y=mx+b 0=mx+b -b=mx x=-b/m Then x intercept(point where line cuts x axis is (-b/m,0) Mark these points and join them. You get the required line.

OpenStudy (anonymous):

Thanks @AravindG . Everything really helps me understand. :D Just to check, is the answer B?

OpenStudy (aravindg):

Just tell me this. What did u get as y intercept and x intercept?

OpenStudy (anonymous):

Let me get my board again XD

OpenStudy (aravindg):

Okay :)

OpenStudy (anonymous):

The y intercept is b=-4

OpenStudy (aravindg):

Good :) x intercept?

OpenStudy (anonymous):

1/3? or is that something else XD

OpenStudy (anonymous):

:) Getting a hang of it

OpenStudy (aravindg):

Check my working above: x=-b/m

OpenStudy (aravindg):

Your b is -4 and m is 1/3

OpenStudy (anonymous):

Wait its -5

OpenStudy (anonymous):

Oooh! I must have been talking about the slope XD I'm mixed up sometimes.

OpenStudy (aravindg):

-5? O.O

OpenStudy (anonymous):

But wait, how did you get -5? XDD

OpenStudy (aravindg):

@DJ♬Øϟϟ¥ so what did u get for x intercept?

OpenStudy (anonymous):

y = -1/3(3) - 4 y = -1 - 4 y = -5

OpenStudy (aravindg):

@Gator153760 You have to substitute 0 not 3!!

OpenStudy (anonymous):

3,-3?

OpenStudy (anonymous):

Ahh crap

OpenStudy (anonymous):

Ignore what I said

OpenStudy (aravindg):

Remember when we want to find x or y intercept we put the other variable ALWAYS to 0.

OpenStudy (aravindg):

@DJ♬Øϟϟ¥ I am waiting...

OpenStudy (anonymous):

Sorry, I don't know DX

OpenStudy (anonymous):

I was thinkin' it was B bcuz the line goes through the y intercept. I thought that was good enough.

OpenStudy (aravindg):

It is isnt that hard. \[x=\dfrac{-b}{m}\] \[x=\dfrac{-(-4)}{\dfrac{1}{3}}\] \[x=4 \times 3=12\]

OpenStudy (aravindg):

That isnt enough because option c also passes through y=-4

OpenStudy (anonymous):

oh (つд`) duh. Ok I'm gonna try to do the next one of these.

OpenStudy (aravindg):

Good :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!