find all solutions of the trigonometric equation
2cos(x) + tan(x) = sec(x)
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OpenStudy (evanhelps):
So first thing you want to do is simplify everything into sine and cosine:
2cos(x) + sin(x)/cos(x) = 1/cos(x)
Then simplify down:
2cos^2(x) + sin(x) = 1
A trigonometric identity states that 2cos^2(x) = 1 - sin^2(x) so:
1 - sin^2(x) + sin(x) = 1
-sin^2(x) + sin(x) = 0
Then you can substitute all terms sin(x) as a letter and solve as a quadratic.
-u^2 + u = 0
And solve the quadratic to get solutions (0, 1)
OpenStudy (anonymous):
Oh, thanks!
OpenStudy (anonymous):
Then do I plug the solutions back into the original equation?
OpenStudy (evanhelps):
Yeah to test it.
OpenStudy (evanhelps):
But I might be wrong if I messed up an identity or something
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OpenStudy (evanhelps):
Hold on I'll check it
OpenStudy (anonymous):
Okay
OpenStudy (evanhelps):
Yeah I did something wrong. Sorry I don't really remember trig identities that well
OpenStudy (evanhelps):
Do you have a sheet with them on it?
OpenStudy (anonymous):
The identities?
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