find all solutions of the trigonometric equation 2cos(x) + tan(x) = sec(x)
So first thing you want to do is simplify everything into sine and cosine: 2cos(x) + sin(x)/cos(x) = 1/cos(x) Then simplify down: 2cos^2(x) + sin(x) = 1 A trigonometric identity states that 2cos^2(x) = 1 - sin^2(x) so: 1 - sin^2(x) + sin(x) = 1 -sin^2(x) + sin(x) = 0 Then you can substitute all terms sin(x) as a letter and solve as a quadratic. -u^2 + u = 0 And solve the quadratic to get solutions (0, 1)
Oh, thanks!
Then do I plug the solutions back into the original equation?
Yeah to test it.
But I might be wrong if I messed up an identity or something
Hold on I'll check it
Okay
Yeah I did something wrong. Sorry I don't really remember trig identities that well
Do you have a sheet with them on it?
The identities?
Cos^2(x) + sin^2(x) = 1
1+tan^2(x)=sec^2(x) 1+cot^2(x)=csc^2(x)
Sorry man I can't figure this one out
It's good thanks anyways
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