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What is the anti derivative of sin(4t)cos(4t) and what method would you use?
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First, we can simplify the expression. You can use a trig identity to combine the sine and cosine into a single trig function. Does it remind you of any particular identity?
Tan?
\[Sin(2a) = 2Sin(a)Cos(a)\]
so, Sin(4t)Cos(4t) = 4sin(t)cos(t)?
Not quite. In this case, a = 4t. Sin(4t)Cos(4t) = (1/2)Sin(8t)
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What formula or rule are you using?
Half angle formula for sine (or double angle, something like that, I forget the name)
so, what do you do after you get Sin(4t)Cos(4t) = (1/2)Sin(8t)
Do a u substitution. u =8t
If I'm saying anything that you haven't heard about at this point, let me know.
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Alright, and du=8?
8 dt, yeah
then, you get |dw:1398912854078:dw|?
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