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First question help. How do i change this to summation series? 49+47+45+.. for 15 terms?
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So you need to find the n'th term of that series. Do you see any pattern in that series ?
-2 :)
good! thats you common difference d= - 2 use the general formula for the n'th term of arithmetic sequence \(\large a_n = a_1 +(n-1)d\) a1 = 1st term = 49 here :)
So it would be 49+(n-1)-2?
careful with brackets ! 49 + (n-1)(-2) and yes, simplify this...
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so would it be 51-2n?
thats correct! \(\Large \sum \limits_{n=1}^{15}51-2n\)
@hartnn thanks so muchh
welcome ^_^ and since you're new here, \(\Huge \mathcal{\text{Welcome To OpenStudy}\ddot\smile} \)
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