Question

Derivatives

Answer 1

\[\huge y = 2\sin (\omega x + \phi) \]
where omega and phi are constants

Answer 2

@ganeshie8

Answer 3

We have to use chain rule here i think

Answer 4

chain rule again

Answer 5

yeah

Answer 6

so what do you think it will be

Answer 7

Wait

Answer 8

\[\huge 2\omega \cos(\omega x +\phi)\]

Answer 9

I took some time as i just learnt calculus today i will get faster with time

Answer 10

you're doing great :)

formally, chain rule goes like this :
\(\large \dfrac{dy}{dx} = \dfrac{dy}{dt} \times \dfrac{dt}{dr}\times \dfrac{dr}{ds}... ~~~\times \dfrac{dz}{dx}\)

Answer 11

oh i see!!

Answer 12

if :
y = f(t),
t = f(r),
r = f(s),
....
z = f(x)

then, to find dy/dx u can use chain rule like above^

Answer 13

instead of looking at definition, i think u wil understand it more easily by doing practice problems :)

Answer 14

yesss