Question

arcsin(sin(-3pi/4))

Answer 1

Are you suppose to solve that?

Answer 2

yeah it says compute

Answer 3

Before I start, Is there any answer choices? If so, post them.

Answer 4

no :( sorry

Answer 5

Arcsin and sin are inverse operations, so arcsin(sin(x)) = x
f(x) = arcsin(sin(3pi/4))
f'(x)= 1/sqrt(1-x^2)
where x= sin (3pi/4)
f'(x) = 1/sqrt(1-(sin(3pi/4))^2)
from trignometric equations
1-sin^2(x) = cos^2(x)
so f'(x) = 1/sqrt(cos^2(3pi/4))
=1/cos(3pi/4)
= 1/cos(3*180/4)
=1/cos(135)
= -1/0.71
the answer is -1.408

Answer 6

thanks! :) do you know what the answer n radians is?

Answer 7

That's all what i could have done... I have done my best, tried my best! Everything I could do!:)