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Mathematics 14 Online
OpenStudy (anonymous):

How would I go about finding this? Someone help please! Attachment below.

OpenStudy (anonymous):

OpenStudy (amistre64):

split the terms to match the sequence

OpenStudy (anonymous):

Which equation would I use and what would I plug in?

OpenStudy (amistre64):

if we start with t1 = 1 then t1*r = t2 = r then t2*r = t3 = r*r then t3*r = t4 = r*r*r then t4*r = t5 = r*r*r*r = 256

OpenStudy (anonymous):

I'm sorry. I don't understand. @whpalmer4

OpenStudy (amistre64):

how do you define the terms of a geometric sequence?

OpenStudy (anonymous):

I seriously do not not know. I'm very confused.

OpenStudy (amistre64):

a geometric sequence is generated by multiplying some common value to each term to get the next term in the sequence. as opposed to an arithmetic sequence which is generated by adding a common value instead

OpenStudy (anonymous):

Does it have a specific formula to which I could plug in these numbers? And @aa123 Do NOT post your question on mine, I have already reported you. Go away.

OpenStudy (amistre64):

spose the common value here is, r. the first term given is: 1 the next term is just: 1*r the next term is: 1*r*r the next term is: 1*r*r*r and the last term is 1*r*r*r*r which is equal to 256 as given solving for r would be paramount to me

OpenStudy (anonymous):

But I need to find the three numbers in between and that doesn't help me find those.

OpenStudy (amistre64):

we can generate an explicit form such that:\[t_n=t_1*r^{n-1}\]

OpenStudy (anonymous):

Can you please tell me what to plug in?

OpenStudy (amistre64):

i just did, in the simplest terms i know how. good luck with it

OpenStudy (anonymous):

Wow, thanks I guess

OpenStudy (sleepyjess):

if you can't think of any other way to do it then just plug in a number for r that sounds reasonable to you and try it

OpenStudy (anonymous):

I can't risk getting this problem wrong. I'm closing this question, no one can help me.

OpenStudy (sleepyjess):

just try plugging in a number \[t _{4}=t _{1}*6 ^{4-1}\] 6^3 is 216 6 isn't the answer so try 7 or 8

OpenStudy (sleepyjess):

are there answer choices?

OpenStudy (whpalmer4):

you have a sequence \( { 1, a,b,c,256}\) and you don't know the values of \(a,b,c\). The problem asks for the missing geometric means, so there is some number \(r\) which will give us the following: \[a = 1*r\]\[b = a*r = 1*r*r\]\[c=b*r = a*r*r = 1*r*r*r\]and finally\[256 = c*r = b*r*r=a*r*r*r = 1*r*r*r*r\] Can you find a number \(r\) such that \(r*r*r*r = 256\)? I think you can by trial and error, or you could use logarithms or square roots. Once you have the value of \(r\), you can find the missing values of the sequence by plugging it into the equations above.

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